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23211120130020 = 223251941193857687
BaseRepresentation
bin1010100011100010000101…
…00100011111011111100100
310001011221221212111121020200
411101301002210133133210
511020242333223130040
6121211012534430500
74613643123541104
oct521610244373744
9101157855447220
1023211120130020
117439865223209
12272a579202430
13cc4a50bcb5a4
145a35d2057204
152a3b93e1c630
hex151c4291f7e4

23211120130020 has 288 divisors, whose sum is σ = 76313784718080. Its totient is φ = 5691192606720.

The previous prime is 23211120130007. The next prime is 23211120130111. The reversal of 23211120130020 is 2003102111232.

23211120130020 is a `hidden beast` number, since 2 + 32 + 111 + 201 + 300 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 23211120129975 and 23211120130002.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 26633617 + ... + 27491303.

It is an arithmetic number, because the mean of its divisors is an integer number (264978419160).

Almost surely, 223211120130020 is an apocalyptic number.

23211120130020 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 23211120130020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (38156892359040).

23211120130020 is an abundant number, since it is smaller than the sum of its proper divisors (53102664588060).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

23211120130020 is a wasteful number, since it uses less digits than its factorization.

23211120130020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 857955 (or 857950 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 23211120130020 its reverse (2003102111232), we get a palindrome (25214222241252).

The spelling of 23211120130020 in words is "twenty-three trillion, two hundred eleven billion, one hundred twenty million, one hundred thirty thousand, twenty".