Base | Representation |
---|---|
bin | 1010100011100110100110… |
… | …00011110000001100100011 |
3 | 10001012012012210220100111001 |
4 | 11101303103003300030203 |
5 | 11020312314311302003 |
6 | 121212053251532431 |
7 | 4614060160266601 |
oct | 521632303601443 |
9 | 101165183810431 |
10 | 23213544244003 |
11 | 743a8996059a3 |
12 | 272ab34bba117 |
13 | cc50491ab069 |
14 | 5a3781d92871 |
15 | 2a3c86b5861d |
hex | 151cd30f0323 |
23213544244003 has 8 divisors (see below), whose sum is σ = 23229835109936. Its totient is φ = 23197254854400.
The previous prime is 23213544243973. The next prime is 23213544244039. The reversal of 23213544244003 is 30044244531232.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 23213544244003 - 213 = 23213544235811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23213544244703) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32088763 + ... + 32804203.
It is an arithmetic number, because the mean of its divisors is an integer number (2903729388742).
Almost surely, 223213544244003 is an apocalyptic number.
23213544244003 is a deficient number, since it is larger than the sum of its proper divisors (16290865933).
23213544244003 is a wasteful number, since it uses less digits than its factorization.
23213544244003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 738165.
The product of its (nonzero) digits is 276480, while the sum is 37.
Adding to 23213544244003 its reverse (30044244531232), we get a palindrome (53257788775235).
The spelling of 23213544244003 in words is "twenty-three trillion, two hundred thirteen billion, five hundred forty-four million, two hundred forty-four thousand, three".
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