Base | Representation |
---|---|
bin | 1010100100000111011000… |
… | …11101000001000101000111 |
3 | 10001020212122210112212120211 |
4 | 11102003230131001011013 |
5 | 11021104343420310333 |
6 | 121224124255540251 |
7 | 4615252362204340 |
oct | 522035435010507 |
9 | 101225583485524 |
10 | 23231150166343 |
11 | 74473036a7a39 |
12 | 273242922a687 |
13 | cc68c38918a2 |
14 | 5a457231b0c7 |
15 | 2a446761cecd |
hex | 1520ec741147 |
23231150166343 has 16 divisors (see below), whose sum is σ = 29081010934080. Its totient is φ = 18094851242496.
The previous prime is 23231150166311. The next prime is 23231150166347. The reversal of 23231150166343 is 34366105113232.
It is not a de Polignac number, because 23231150166343 - 25 = 23231150166311 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23231150166296 and 23231150166305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23231150166347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3365854296 + ... + 3365861197.
It is an arithmetic number, because the mean of its divisors is an integer number (1817563183380).
Almost surely, 223231150166343 is an apocalyptic number.
23231150166343 is a deficient number, since it is larger than the sum of its proper divisors (5849860767737).
23231150166343 is a wasteful number, since it uses less digits than its factorization.
23231150166343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6731715546.
The product of its (nonzero) digits is 233280, while the sum is 40.
Adding to 23231150166343 its reverse (34366105113232), we get a palindrome (57597255279575).
The spelling of 23231150166343 in words is "twenty-three trillion, two hundred thirty-one billion, one hundred fifty million, one hundred sixty-six thousand, three hundred forty-three".
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