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23233144117 = 83279917399
BaseRepresentation
bin10101101000110011…
…011010010100110101
32012222011021000012011
4111220303122110311
5340040141102432
614401222524221
71451511316021
oct255063322465
965864230164
1023233144117
119942560057
124604896671
13226347c571
1411a585b381
1590ea14847
hex568cda535

23233144117 has 4 divisors (see below), whose sum is σ = 23513061600. Its totient is φ = 22953226636.

The previous prime is 23233144097. The next prime is 23233144133. The reversal of 23233144117 is 71144133232.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23233144117 - 223 = 23224755509 is a prime.

It is a super-2 number, since 2×232331441172 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23233144157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139958617 + ... + 139958782.

It is an arithmetic number, because the mean of its divisors is an integer number (5878265400).

Almost surely, 223233144117 is an apocalyptic number.

It is an amenable number.

23233144117 is a deficient number, since it is larger than the sum of its proper divisors (279917483).

23233144117 is an equidigital number, since it uses as much as digits as its factorization.

23233144117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 279917482.

The product of its digits is 12096, while the sum is 31.

Adding to 23233144117 its reverse (71144133232), we get a palindrome (94377277349).

The spelling of 23233144117 in words is "twenty-three billion, two hundred thirty-three million, one hundred forty-four thousand, one hundred seventeen".

Divisors: 1 83 279917399 23233144117