Base | Representation |
---|---|
bin | 1010100100001101011100… |
… | …11001011111001111111011 |
3 | 10001021012001120020211101021 |
4 | 11102012232121133033323 |
5 | 11021133024412134433 |
6 | 121225423213203311 |
7 | 4615426122415642 |
oct | 522065631371773 |
9 | 101235046224337 |
10 | 23234404021243 |
11 | 7448723394318 |
12 | 2732b96a90537 |
13 | cc6cc1a3830c |
14 | 5a47a0524359 |
15 | 2a45a810822d |
hex | 1521ae65f3fb |
23234404021243 has 4 divisors (see below), whose sum is σ = 23862360886720. Its totient is φ = 22606447155768.
The previous prime is 23234404021237. The next prime is 23234404021247. The reversal of 23234404021243 is 34212040443232.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 23234404021243 - 217 = 23234403890171 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23234404021199 and 23234404021208.
It is not an unprimeable number, because it can be changed into a prime (23234404021247) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 313978432683 + ... + 313978432756.
It is an arithmetic number, because the mean of its divisors is an integer number (5965590221680).
Almost surely, 223234404021243 is an apocalyptic number.
23234404021243 is a deficient number, since it is larger than the sum of its proper divisors (627956865477).
23234404021243 is an equidigital number, since it uses as much as digits as its factorization.
23234404021243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 627956865476.
The product of its (nonzero) digits is 110592, while the sum is 34.
Adding to 23234404021243 its reverse (34212040443232), we get a palindrome (57446444464475).
The spelling of 23234404021243 in words is "twenty-three trillion, two hundred thirty-four billion, four hundred four million, twenty-one thousand, two hundred forty-three".
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