Base | Representation |
---|---|
bin | 110100110111011000010100… |
… | …010110110111011001000011 |
3 | 1010111020011201120101212202111 |
4 | 310313120110112313121003 |
5 | 220433321344342440120 |
6 | 2142254524242400151 |
7 | 66654603241346104 |
oct | 6467302426673103 |
9 | 1114204646355674 |
10 | 232504101140035 |
11 | 680a04877a690a |
12 | 220b0a29060057 |
13 | 9c9707295432a |
14 | 415b3896043ab |
15 | 1bd2e72a2b75a |
hex | d376145b7643 |
232504101140035 has 48 divisors (see below), whose sum is σ = 282335066155296. Its totient is φ = 183801461760000.
The previous prime is 232504101140021. The next prime is 232504101140063. The reversal of 232504101140035 is 530041101405232.
It is not a de Polignac number, because 232504101140035 - 239 = 231954345326147 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 232504101139979 and 232504101140006.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 38171742340 + ... + 38171748430.
It is an arithmetic number, because the mean of its divisors is an integer number (5881980544902).
Almost surely, 2232504101140035 is an apocalyptic number.
232504101140035 is a deficient number, since it is larger than the sum of its proper divisors (49830965015261).
232504101140035 is an equidigital number, since it uses as much as digits as its factorization.
232504101140035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7336 (or 6935 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 232504101140035 its reverse (530041101405232), we get a palindrome (762545202545267).
The spelling of 232504101140035 in words is "two hundred thirty-two trillion, five hundred four billion, one hundred one million, one hundred forty thousand, thirty-five".
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