Base | Representation |
---|---|
bin | 1010100110010001001010… |
… | …11010110010010111101001 |
3 | 10001111221120220110101020002 |
4 | 11103020211122302113221 |
5 | 11023312341300432040 |
6 | 121322120253112345 |
7 | 4623511415201666 |
oct | 523104532622751 |
9 | 101457526411202 |
10 | 23305120327145 |
11 | 7475711952638 |
12 | 27448317886b5 |
13 | 10008816b0bc7 |
14 | 5a7d8c31aa6d |
15 | 2a634655ca15 |
hex | 1532256b25e9 |
23305120327145 has 8 divisors (see below), whose sum is σ = 27967712196480. Its totient is φ = 18643051059120.
The previous prime is 23305120327091. The next prime is 23305120327157. The reversal of 23305120327145 is 54172302150332.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 23305120327145 - 212 = 23305120323049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23305120327099 and 23305120327108.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 130552211 + ... + 130730600.
It is an arithmetic number, because the mean of its divisors is an integer number (3495964024560).
Almost surely, 223305120327145 is an apocalyptic number.
It is an amenable number.
23305120327145 is a deficient number, since it is larger than the sum of its proper divisors (4662591869335).
23305120327145 is a wasteful number, since it uses less digits than its factorization.
23305120327145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 261300655.
The product of its (nonzero) digits is 151200, while the sum is 38.
Adding to 23305120327145 its reverse (54172302150332), we get a palindrome (77477422477477).
The spelling of 23305120327145 in words is "twenty-three trillion, three hundred five billion, one hundred twenty million, three hundred twenty-seven thousand, one hundred forty-five".
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