Base | Representation |
---|---|
bin | 100001111010111010100… |
… | …110110001010100110001 |
3 | 22020211201121101110120122 |
4 | 201322322212301110301 |
5 | 301142343232000423 |
6 | 4542503100020025 |
7 | 330260266404014 |
oct | 41727246612461 |
9 | 8224647343518 |
10 | 2331003000113 |
11 | 819633473a27 |
12 | 317920231615 |
13 | 13ba744a5958 |
14 | 80b6d32937b |
15 | 4097c38a8c8 |
hex | 21eba9b1531 |
2331003000113 has 64 divisors (see below), whose sum is σ = 2583023040000. Its totient is φ = 2095058939904.
The previous prime is 2331003000083. The next prime is 2331003000127. The reversal of 2331003000113 is 3110003001332.
2331003000113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 2331003000113 - 222 = 2330998805809 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2331003000091 and 2331003000100.
It is not an unprimeable number, because it can be changed into a prime (2331003000133) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4786453556 + ... + 4786454042.
It is an arithmetic number, because the mean of its divisors is an integer number (40359735000).
Almost surely, 22331003000113 is an apocalyptic number.
It is an amenable number.
2331003000113 is a deficient number, since it is larger than the sum of its proper divisors (252020039887).
2331003000113 is a wasteful number, since it uses less digits than its factorization.
2331003000113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1194.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 2331003000113 its reverse (3110003001332), we get a palindrome (5441006001445).
The spelling of 2331003000113 in words is "two trillion, three hundred thirty-one billion, three million, one hundred thirteen", and thus it is an aban number.
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