Base | Representation |
---|---|
bin | 1010100110011110001110… |
… | …10010110000110111011010 |
3 | 10001112121200111110112202111 |
4 | 11103033013102300313122 |
5 | 11023421221030200442 |
6 | 121325240054222534 |
7 | 4624150224610234 |
oct | 523170722606732 |
9 | 101477614415674 |
10 | 23312131100122 |
11 | 747868a295097 |
12 | 2746069654a4a |
13 | 100142acb9497 |
14 | 5a845547d254 |
15 | 2a6606ca3b17 |
hex | 1533c74b0dda |
23312131100122 has 4 divisors (see below), whose sum is σ = 34968196650186. Its totient is φ = 11656065550060.
The previous prime is 23312131099981. The next prime is 23312131100129. The reversal of 23312131100122 is 22100113121332.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 20068706595721 + 3243424504401 = 4479811^2 + 1800951^2 .
It is a junction number, because it is equal to n+sod(n) for n = 23312131100093 and 23312131100102.
It is not an unprimeable number, because it can be changed into a prime (23312131100129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5828032775029 + ... + 5828032775032.
Almost surely, 223312131100122 is an apocalyptic number.
23312131100122 is a deficient number, since it is larger than the sum of its proper divisors (11656065550064).
23312131100122 is a wasteful number, since it uses less digits than its factorization.
23312131100122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11656065550063.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 23312131100122 its reverse (22100113121332), we get a palindrome (45412244221454).
The spelling of 23312131100122 in words is "twenty-three trillion, three hundred twelve billion, one hundred thirty-one million, one hundred thousand, one hundred twenty-two".
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