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23312441131 = 723144797771
BaseRepresentation
bin10101101101100001…
…111001111100101011
32020011200110201020121
4111231201321330223
5340220441104011
614413134304111
71453463323450
oct255541717453
966150421217
1023312441131
1199832a1081
124627358037
132276a24985
1411b21bd827
15916979e71
hex56d879f2b

23312441131 has 8 divisors (see below), whose sum is σ = 27801172224. Its totient is φ = 19113305640.

The previous prime is 23312441129. The next prime is 23312441147. The reversal of 23312441131 is 13114421332.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 23312441131 - 21 = 23312441129 is a prime.

It is a super-2 number, since 2×233124411312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23312441096 and 23312441105.

It is not an unprimeable number, because it can be changed into a prime (23312441101) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 72398725 + ... + 72399046.

It is an arithmetic number, because the mean of its divisors is an integer number (3475146528).

Almost surely, 223312441131 is an apocalyptic number.

23312441131 is a deficient number, since it is larger than the sum of its proper divisors (4488731093).

23312441131 is a wasteful number, since it uses less digits than its factorization.

23312441131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 144797801.

The product of its digits is 1728, while the sum is 25.

Adding to 23312441131 its reverse (13114421332), we get a palindrome (36426862463).

The spelling of 23312441131 in words is "twenty-three billion, three hundred twelve million, four hundred forty-one thousand, one hundred thirty-one".

Divisors: 1 7 23 161 144797771 1013584397 3330348733 23312441131