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2331313011300 = 2235271392412
BaseRepresentation
bin100001111011001101000…
…101010111101001100100
322020212112012201122222110
4201323031011113221210
5301144012112330200
64542553532401020
7330301052430510
oct41731505275144
98225465648873
102331313011300
11819782465a19
123179a8016170
1313bac379a420
1480b9c587140
15409996c5b50
hex21ecd157a64

2331313011300 has 216 divisors, whose sum is σ = 8302763880768. Its totient is φ = 491828198400.

The previous prime is 2331313011289. The next prime is 2331313011311. The reversal of 2331313011300 is 31103131332.

2331313011300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (2331313011289) and next prime (2331313011311).

It is a Harshad number since it is a multiple of its sum of digits (21).

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 252274680 + ... + 252283920.

Almost surely, 22331313011300 is an apocalyptic number.

2331313011300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2331313011300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4151381940384).

2331313011300 is an abundant number, since it is smaller than the sum of its proper divisors (5971450869468).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2331313011300 is an equidigital number, since it uses as much as digits as its factorization.

2331313011300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18519 (or 9271 counting only the distinct ones).

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 2331313011300 its reverse (31103131332), we get a palindrome (2362416142632).

The spelling of 2331313011300 in words is "two trillion, three hundred thirty-one billion, three hundred thirteen million, eleven thousand, three hundred".