Base | Representation |
---|---|
bin | 1101100100011111000… |
… | …0000000011101001111 |
3 | 211021202100222201200101 |
4 | 3121013300000131033 |
5 | 12304423243013403 |
6 | 255033243511531 |
7 | 22562141212261 |
oct | 3310760003517 |
9 | 737670881611 |
10 | 233132001103 |
11 | 8a963a33aa1 |
12 | 392235285a7 |
13 | 18ca4535061 |
14 | b3d8493b31 |
15 | 60e701871d |
hex | 3647c0074f |
233132001103 has 4 divisors (see below), whose sum is σ = 243268175088. Its totient is φ = 222995827120.
The previous prime is 233132001083. The next prime is 233132001119. The reversal of 233132001103 is 301100231332.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-233132001103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (233132001133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5068086958 + ... + 5068087003.
It is an arithmetic number, because the mean of its divisors is an integer number (60817043772).
Almost surely, 2233132001103 is an apocalyptic number.
233132001103 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
233132001103 is a deficient number, since it is larger than the sum of its proper divisors (10136173985).
233132001103 is a wasteful number, since it uses less digits than its factorization.
233132001103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10136173984.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 233132001103 its reverse (301100231332), we get a palindrome (534232232435).
The spelling of 233132001103 in words is "two hundred thirty-three billion, one hundred thirty-two million, one thousand, one hundred three".
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