Base | Representation |
---|---|
bin | 110101000000101100111101… |
… | …001100111100111010010001 |
3 | 1010120111102022112220211121222 |
4 | 311000230331030330322101 |
5 | 221024320410023043121 |
6 | 2143505114030254425 |
7 | 100052102625346664 |
oct | 6500547514747221 |
9 | 1116442275824558 |
10 | 233144736534161 |
11 | 68318144780461 |
12 | 22195018657415 |
13 | a0125ba1a2c3a |
14 | 41803a05b36db |
15 | 1be496a0410ab |
hex | d40b3d33ce91 |
233144736534161 has 16 divisors (see below), whose sum is σ = 235549424355840. Its totient is φ = 230741949979200.
The previous prime is 233144736534113. The next prime is 233144736534167. The reversal of 233144736534161 is 161435637441332.
233144736534161 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-233144736534161 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (233144736534167) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5649370835 + ... + 5649412103.
It is an arithmetic number, because the mean of its divisors is an integer number (14721839022240).
Almost surely, 2233144736534161 is an apocalyptic number.
It is an amenable number.
233144736534161 is a deficient number, since it is larger than the sum of its proper divisors (2404687821679).
233144736534161 is a wasteful number, since it uses less digits than its factorization.
233144736534161 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62896.
The product of its digits is 13063680, while the sum is 53.
The spelling of 233144736534161 in words is "two hundred thirty-three trillion, one hundred forty-four billion, seven hundred thirty-six million, five hundred thirty-four thousand, one hundred sixty-one".
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