Base | Representation |
---|---|
bin | 1010100110101101101011… |
… | …00010011001101111011011 |
3 | 10001120102002101102001002221 |
4 | 11103112311202121233123 |
5 | 11024040211311110121 |
6 | 121333130545404511 |
7 | 4624562553043411 |
oct | 523266542315733 |
9 | 101512071361087 |
10 | 23320423144411 |
11 | 74811549a2758 |
12 | 27477a2639737 |
13 | 100214cba3173 |
14 | 5a8a008492b1 |
15 | 2a693ec3ab41 |
hex | 1535b5899bdb |
23320423144411 has 4 divisors (see below), whose sum is σ = 23321118624912. Its totient is φ = 23319727663912.
The previous prime is 23320423144397. The next prime is 23320423144429. The reversal of 23320423144411 is 11444132402332.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23320423144411 - 25 = 23320423144379 is a prime.
It is a super-4 number, since 4×233204231444114 (a number of 55 digits) contains 4444 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23320423144481) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 347689951 + ... + 347757016.
It is an arithmetic number, because the mean of its divisors is an integer number (5830279656228).
Almost surely, 223320423144411 is an apocalyptic number.
23320423144411 is a deficient number, since it is larger than the sum of its proper divisors (695480501).
23320423144411 is an equidigital number, since it uses as much as digits as its factorization.
23320423144411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 695480500.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 23320423144411 its reverse (11444132402332), we get a palindrome (34764555546743).
The spelling of 23320423144411 in words is "twenty-three trillion, three hundred twenty billion, four hundred twenty-three million, one hundred forty-four thousand, four hundred eleven".
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