Base | Representation |
---|---|
bin | 1010100111000000010101… |
… | …01001100100001100101001 |
3 | 10001121100221112210212012121 |
4 | 11103200022221210030221 |
5 | 11024221220400121301 |
6 | 121341505011311241 |
7 | 4625366035426360 |
oct | 523401251441451 |
9 | 101540845725177 |
10 | 23330441020201 |
11 | 7485425807047 |
12 | 27497195ab521 |
13 | 10030884abc13 |
14 | 5a92b11027d7 |
15 | 2a6d2947a3a1 |
hex | 15380aa64329 |
23330441020201 has 4 divisors (see below), whose sum is σ = 26663361165952. Its totient is φ = 19997520874452.
The previous prime is 23330441020199. The next prime is 23330441020253. The reversal of 23330441020201 is 10202014403332.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 23330441020201 - 21 = 23330441020199 is a prime.
It is not an unprimeable number, because it can be changed into a prime (23330441020291) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1666460072865 + ... + 1666460072878.
It is an arithmetic number, because the mean of its divisors is an integer number (6665840291488).
Almost surely, 223330441020201 is an apocalyptic number.
It is an amenable number.
23330441020201 is a deficient number, since it is larger than the sum of its proper divisors (3332920145751).
23330441020201 is an equidigital number, since it uses as much as digits as its factorization.
23330441020201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3332920145750.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 23330441020201 its reverse (10202014403332), we get a palindrome (33532455423533).
The spelling of 23330441020201 in words is "twenty-three trillion, three hundred thirty billion, four hundred forty-one million, twenty thousand, two hundred one".
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