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233331221011234 = 2116665610505617
BaseRepresentation
bin110101000011011010101000…
…100010110001101100100010
31010121011020122222100211011011
4311003122220202301230202
5221040344320034324414
62144130514432011134
7100101424113301033
oct6503325042615442
91117136588324134
10233331221011234
116838a2403681a5
12222051a1990aaa
13a027069391968
144189411692a8a
151be9731b80dc4
hexd436a88b1b22

233331221011234 has 4 divisors (see below), whose sum is σ = 349996831516854. Its totient is φ = 116665610505616.

The previous prime is 233331221011177. The next prime is 233331221011253. The reversal of 233331221011234 is 432110122133332.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 132212167706025 + 101119053305209 = 11498355^2 + 10055797^2 .

It is a junction number, because it is equal to n+sod(n) for n = 233331221011196 and 233331221011205.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58332805252807 + ... + 58332805252810.

Almost surely, 2233331221011234 is an apocalyptic number.

233331221011234 is a deficient number, since it is larger than the sum of its proper divisors (116665610505620).

233331221011234 is a wasteful number, since it uses less digits than its factorization.

233331221011234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 116665610505619.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 233331221011234 its reverse (432110122133332), we get a palindrome (665441343144566).

It can be divided in two parts, 23333122 and 1011234, that added together give a square (24344356 = 49342).

The spelling of 233331221011234 in words is "two hundred thirty-three trillion, three hundred thirty-one billion, two hundred twenty-one million, eleven thousand, two hundred thirty-four".

Divisors: 1 2 116665610505617 233331221011234