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2335533140132 = 22701983186107
BaseRepresentation
bin100001111111001000100…
…111111000100010100100
322021021102022122102102022
4201333020213320202210
5301231132440441012
64544532404402312
7330510455065223
oct41771047704244
98237368572368
102335533140132
118205486301a5
123187853a6398
1313c316ba308a
148107cc3ccba
1540b44e2e472
hex21fc89f88a4

2335533140132 has 12 divisors (see below), whose sum is σ = 4087765347120. Its totient is φ = 1167600183816.

The previous prime is 2335533140111. The next prime is 2335533140177. The reversal of 2335533140132 is 2310413355332.

It is a super-3 number, since 3×23355331401323 (a number of 38 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2335533140092 and 2335533140101.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41564978 + ... + 41621129.

It is an arithmetic number, because the mean of its divisors is an integer number (340647112260).

Almost surely, 22335533140132 is an apocalyptic number.

It is an amenable number.

2335533140132 is a deficient number, since it is larger than the sum of its proper divisors (1752232206988).

2335533140132 is a wasteful number, since it uses less digits than its factorization.

2335533140132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83193130 (or 83193128 counting only the distinct ones).

The product of its (nonzero) digits is 97200, while the sum is 35.

Adding to 2335533140132 its reverse (2310413355332), we get a palindrome (4645946495464).

The spelling of 2335533140132 in words is "two trillion, three hundred thirty-five billion, five hundred thirty-three million, one hundred forty thousand, one hundred thirty-two".

Divisors: 1 2 4 7019 14038 28076 83186107 166372214 332744428 583883285033 1167766570066 2335533140132