Base | Representation |
---|---|
bin | 10101110010110010… |
… | …000011011000000011 |
3 | 2020101211021121210021 |
4 | 111302302003120003 |
5 | 340411020411011 |
6 | 14430003114311 |
7 | 1455613323244 |
oct | 256262033003 |
9 | 66354247707 |
10 | 23400560131 |
11 | 9a190081a3 |
12 | 4650972997 |
13 | 228c0686b0 |
14 | 11bdb9accb |
15 | 91e584471 |
hex | 572c83603 |
23400560131 has 4 divisors (see below), whose sum is σ = 25200603232. Its totient is φ = 21600517032.
The previous prime is 23400560119. The next prime is 23400560137. The reversal of 23400560131 is 13106500432.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23400560131 - 213 = 23400551939 is a prime.
It is a super-2 number, since 2×234005601312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23400560096 and 23400560105.
It is not an unprimeable number, because it can be changed into a prime (23400560137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 900021531 + ... + 900021556.
It is an arithmetic number, because the mean of its divisors is an integer number (6300150808).
Almost surely, 223400560131 is an apocalyptic number.
23400560131 is a deficient number, since it is larger than the sum of its proper divisors (1800043101).
23400560131 is a wasteful number, since it uses less digits than its factorization.
23400560131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1800043100.
The product of its (nonzero) digits is 2160, while the sum is 25.
The spelling of 23400560131 in words is "twenty-three billion, four hundred million, five hundred sixty thousand, one hundred thirty-one".
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