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234013113403 = 1738935386831
BaseRepresentation
bin1101100111110001000…
…1001011110000111011
3211101000202221212112021
43121330101023300323
512313224324112103
6255300521055311
722623030433636
oct3317421136073
9741022855467
10234013113403
1190276335783
123942a627537
13190b4c47694
14b47d4d4c1d
156149563bbd
hex367c44bc3b

234013113403 has 8 divisors (see below), whose sum is σ = 248415560640. Its totient is φ = 219681440640.

The previous prime is 234013113359. The next prime is 234013113409. The reversal of 234013113403 is 304311310432.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 234013113403 - 233 = 225423178811 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (234013113409) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17686803 + ... + 17700028.

It is an arithmetic number, because the mean of its divisors is an integer number (31051945080).

Almost surely, 2234013113403 is an apocalyptic number.

234013113403 is a deficient number, since it is larger than the sum of its proper divisors (14402447237).

234013113403 is a wasteful number, since it uses less digits than its factorization.

234013113403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35387237.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 234013113403 its reverse (304311310432), we get a palindrome (538324423835).

The spelling of 234013113403 in words is "two hundred thirty-four billion, thirteen million, one hundred thirteen thousand, four hundred three".

Divisors: 1 17 389 6613 35386831 601576127 13765477259 234013113403