23401410153133 has 4 divisors (see below), whose sum is σ = 23422626301248. Its totient is φ = 23380194005020.

The previous prime is 23401410153131. The next prime is 23401410153151. The reversal of 23401410153133 is 33135101410432.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23401410153133 - 2¹ = 23401410153131 is a prime.

It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23401410153095 and 23401410153104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23401410153131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10608072403 + ... + 10608074608.

It is an arithmetic number, because the mean of its divisors is an integer number (5855656575312).

Almost surely, 2^{23401410153133} is an apocalyptic number.

It is an amenable number.

23401410153133 is a deficient number, since it is larger than the sum of its proper divisors (21216148115).

23401410153133 is a wasteful number, since it uses less digits than its factorization.

23401410153133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21216148114.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 23401410153133 its reverse (33135101410432), we get a palindrome (56536511563565).

The spelling of 23401410153133 in words is "twenty-three trillion, four hundred one billion, four hundred ten million, one hundred fifty-three thousand, one hundred thirty-three".