Base | Representation |
---|---|
bin | 1010101001001001100011… |
… | …01111001010101110101111 |
3 | 10001212102002202022222220122 |
4 | 11110210301233022232233 |
5 | 11031423104434303312 |
6 | 121435411132035155 |
7 | 4633614460126511 |
oct | 524446157125657 |
9 | 101772082288818 |
10 | 23404111244207 |
11 | 750369a7207a1 |
12 | 275ba59602abb |
13 | 1009cc9123145 |
14 | 5aca9d347bb1 |
15 | 2a8bdbdbeb72 |
hex | 154931bcabaf |
23404111244207 has 4 divisors (see below), whose sum is σ = 23418729678816. Its totient is φ = 23389492809600.
The previous prime is 23404111244197. The next prime is 23404111244209. The reversal of 23404111244207 is 70244211140432.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23404111244207 - 216 = 23404111178671 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23404111244209) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7309214903 + ... + 7309218104.
It is an arithmetic number, because the mean of its divisors is an integer number (5854682419704).
Almost surely, 223404111244207 is an apocalyptic number.
23404111244207 is a deficient number, since it is larger than the sum of its proper divisors (14618434609).
23404111244207 is a wasteful number, since it uses less digits than its factorization.
23404111244207 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14618434608.
The product of its (nonzero) digits is 43008, while the sum is 35.
Adding to 23404111244207 its reverse (70244211140432), we get a palindrome (93648322384639).
The spelling of 23404111244207 in words is "twenty-three trillion, four hundred four billion, one hundred eleven million, two hundred forty-four thousand, two hundred seven".
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