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2340431001113 = 47331150442309
BaseRepresentation
bin100010000011101100100…
…011101111011000011001
322021202001122211112120212
4202003230203233120121
5301321200314013423
64551102410500505
7331043030161262
oct42035443573031
98252048745525
102340431001113
11822631315697
12319711734735
1313c91781c67a
14813c5513969
1540d2ee0c578
hex220ec8ef619

2340431001113 has 8 divisors (see below), whose sum is σ = 2397448652160. Its totient is φ = 2283714235440.

The previous prime is 2340431001071. The next prime is 2340431001163. The reversal of 2340431001113 is 3111001340432.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2340431001113 - 214 = 2340430984729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2340431001163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 75205598 + ... + 75236711.

It is an arithmetic number, because the mean of its divisors is an integer number (299681081520).

Almost surely, 22340431001113 is an apocalyptic number.

It is an amenable number.

2340431001113 is a deficient number, since it is larger than the sum of its proper divisors (57017651047).

2340431001113 is a wasteful number, since it uses less digits than its factorization.

2340431001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 150442687.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 2340431001113 its reverse (3111001340432), we get a palindrome (5451432341545).

The spelling of 2340431001113 in words is "two trillion, three hundred forty billion, four hundred thirty-one million, one thousand, one hundred thirteen".

Divisors: 1 47 331 15557 150442309 7070788523 49796404279 2340431001113