234043341131 has 4 divisors (see below), whose sum is σ = 242113801200. Its totient is φ = 225972881064.

The previous prime is 234043341127. The next prime is 234043341163. The reversal of 234043341131 is 131143340432.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 234043341131 - 2² = 234043341127 is a prime.

It is a super-2 number, since 2×234043341131² (a number of 24 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (29), and also a Moran number because the ratio is a prime number: 8070460039 = 234043341131 / (2 + 3 + 4 + 0 + 4 + 3 + 3 + 4 + 1 + 1 + 3 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 234043341094 and 234043341103.

It is not an unprimeable number, because it can be changed into a prime (234043341331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4035229991 + ... + 4035230048.

It is an arithmetic number, because the mean of its divisors is an integer number (60528450300).

Almost surely, 2^234043341131 is an apocalyptic number.

234043341131 is a deficient number, since it is larger than the sum of its proper divisors (8070460069).

234043341131 is an equidigital number, since it uses as much as digits as its factorization.

234043341131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8070460068.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 234043341131 its reverse (131143340432), we get a palindrome (365186681563).

The spelling of 234043341131 in words is "two hundred thirty-four billion, forty-three million, three hundred forty-one thousand, one hundred thirty-one".