23404540333 has 4 divisors (see below), whose sum is σ = 23502467520. Its totient is φ = 23306613148.

The previous prime is 23404540297. The next prime is 23404540349. The reversal of 23404540333 is 33304540432.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-23404540333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23404540295 and 23404540304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23404540633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48963235 + ... + 48963712.

It is an arithmetic number, because the mean of its divisors is an integer number (5875616880).

Almost surely, 2^23404540333 is an apocalyptic number.

It is an amenable number.

23404540333 is a deficient number, since it is larger than the sum of its proper divisors (97927187).

23404540333 is an equidigital number, since it uses as much as digits as its factorization.

23404540333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97927186.

The product of its (nonzero) digits is 51840, while the sum is 31.

Subtracting 23404540333 from its reverse (33304540432), we obtain a palindrome (9900000099).

The spelling of 23404540333 in words is "twenty-three billion, four hundred four million, five hundred forty thousand, three hundred thirty-three".