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234080433 = 3243604859
BaseRepresentation
bin11011111001111…
…00100010110001
3121022110111222200
431330330202301
5434411033213
635121053413
75541436146
oct1574744261
9538414880
10234080433
11110150104
1266487269
133965a642
14231343cd
151583c273
hexdf3c8b1

234080433 has 12 divisors (see below), whose sum is σ = 345979920. Its totient is φ = 152424216.

The previous prime is 234080423. The next prime is 234080449. The reversal of 234080433 is 334080432.

It is not a de Polignac number, because 234080433 - 216 = 234014897 is a prime.

It is a super-3 number, since 3×2340804333 (a number of 26 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 234080397 and 234080406.

It is not an unprimeable number, because it can be changed into a prime (234080423) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 302043 + ... + 302816.

It is an arithmetic number, because the mean of its divisors is an integer number (28831660).

Almost surely, 2234080433 is an apocalyptic number.

It is an amenable number.

234080433 is a deficient number, since it is larger than the sum of its proper divisors (111899487).

234080433 is a wasteful number, since it uses less digits than its factorization.

234080433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 604908 (or 604905 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

The square root of 234080433 is about 15299.6873497467. The cubic root of 234080433 is about 616.2946117383.

Subtracting 234080433 from its reverse (334080432), we obtain a palindrome (99999999).

The spelling of 234080433 in words is "two hundred thirty-four million, eighty thousand, four hundred thirty-three".

Divisors: 1 3 9 43 129 387 604859 1814577 5443731 26008937 78026811 234080433