2341130020133 has 4 divisors (see below), whose sum is σ = 2344323922668. Its totient is φ = 2337936117600.

The previous prime is 2341130020091. The next prime is 2341130020189. The reversal of 2341130020133 is 3310200311432.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1756030473409 + 585099546724 = 1325153^2 + 764918^2 .

It is a cyclic number.

It is not a de Polignac number, because 2341130020133 - 2¹⁴ = 2341130003749 is a prime.

It is a super-3 number, since 3×2341130020133³ (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2341130020099 and 2341130020108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2341130020193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1596950168 + ... + 1596951633.

It is an arithmetic number, because the mean of its divisors is an integer number (586080980667).

Almost surely, 2^{2341130020133} is an apocalyptic number.

It is an amenable number.

2341130020133 is a deficient number, since it is larger than the sum of its proper divisors (3193902535).

2341130020133 is an equidigital number, since it uses as much as digits as its factorization.

2341130020133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3193902534.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 2341130020133 its reverse (3310200311432), we get a palindrome (5651330331565).

The spelling of 2341130020133 in words is "two trillion, three hundred forty-one billion, one hundred thirty million, twenty thousand, one hundred thirty-three".