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234114412113 = 3260742854551
BaseRepresentation
bin1101101000001001001…
…1100110111001010001
3211101021211120101020100
43122002103212321101
512313431242141423
6255314540203013
722625400445311
oct3320223467121
9741254511210
10234114412113
1190318533a1a
1239458539469
13190ccc2434a
14b48cb43441
1561533c3343
hex36824e6e51

234114412113 has 12 divisors (see below), whose sum is σ = 338722379008. Its totient is φ = 155819143800.

The previous prime is 234114412057. The next prime is 234114412183. The reversal of 234114412113 is 311214411432.

It is a happy number.

234114412113 is a `hidden beast` number, since 2 + 3 + 4 + 1 + 1 + 441 + 211 + 3 = 666.

It is not a de Polignac number, because 234114412113 - 217 = 234114281041 is a prime.

It is a super-2 number, since 2×2341144121132 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (234114412183) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 21421813 + ... + 21432738.

Almost surely, 2234114412113 is an apocalyptic number.

It is an amenable number.

234114412113 is a deficient number, since it is larger than the sum of its proper divisors (104607966895).

234114412113 is a wasteful number, since it uses less digits than its factorization.

234114412113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42855164 (or 42855161 counting only the distinct ones).

The product of its digits is 2304, while the sum is 27.

Adding to 234114412113 its reverse (311214411432), we get a palindrome (545328823545).

The spelling of 234114412113 in words is "two hundred thirty-four billion, one hundred fourteen million, four hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 9 607 1821 5463 42854551 128563653 385690959 26012712457 78038137371 234114412113