Base | Representation |
---|---|
bin | 1010101010000011010010… |
… | …00011100111000101111011 |
3 | 10001222101002200220021111010 |
4 | 11111001221003213011323 |
5 | 11032430043123334321 |
6 | 121501534353005003 |
7 | 4636062504211506 |
oct | 525015103470573 |
9 | 101871080807433 |
10 | 23435104121211 |
11 | 7515854362a32 |
12 | 2765a68b53763 |
13 | 100cbc8100213 |
14 | 5b039d5a813d |
15 | 2a9902c6e676 |
hex | 1550690e717b |
23435104121211 has 4 divisors (see below), whose sum is σ = 31246805494952. Its totient is φ = 15623402747472.
The previous prime is 23435104121207. The next prime is 23435104121239. The reversal of 23435104121211 is 11212140153432.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 23435104121211 - 22 = 23435104121207 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23435104021211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3905850686866 + ... + 3905850686871.
It is an arithmetic number, because the mean of its divisors is an integer number (7811701373738).
Almost surely, 223435104121211 is an apocalyptic number.
23435104121211 is a deficient number, since it is larger than the sum of its proper divisors (7811701373741).
23435104121211 is an equidigital number, since it uses as much as digits as its factorization.
23435104121211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7811701373740.
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 23435104121211 its reverse (11212140153432), we get a palindrome (34647244274643).
The spelling of 23435104121211 in words is "twenty-three trillion, four hundred thirty-five billion, one hundred four million, one hundred twenty-one thousand, two hundred eleven".
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