Base | Representation |
---|---|
bin | 1010101010010010100100… |
… | …11010111101110001011010 |
3 | 10002000011021212210200021122 |
4 | 11111021102122331301122 |
5 | 11033043401430131132 |
6 | 121505413201405242 |
7 | 4636503116460665 |
oct | 525112232756132 |
9 | 102004255720248 |
10 | 23443314302042 |
11 | 7519287837348 |
12 | 276757a639822 |
13 | 101090605359b |
14 | 5b093bb446dc |
15 | 2a9c33935912 |
hex | 1552526bdc5a |
23443314302042 has 4 divisors (see below), whose sum is σ = 35164971453066. Its totient is φ = 11721657151020.
The previous prime is 23443314302017. The next prime is 23443314302071. The reversal of 23443314302042 is 24020341334432.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 22093374728881 + 1349939573161 = 4700359^2 + 1161869^2 .
It is a junction number, because it is equal to n+sod(n) for n = 23443314301993 and 23443314302011.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5860828575509 + ... + 5860828575512.
Almost surely, 223443314302042 is an apocalyptic number.
23443314302042 is a deficient number, since it is larger than the sum of its proper divisors (11721657151024).
23443314302042 is a wasteful number, since it uses less digits than its factorization.
23443314302042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11721657151023.
The product of its (nonzero) digits is 165888, while the sum is 35.
Adding to 23443314302042 its reverse (24020341334432), we get a palindrome (47463655636474).
The spelling of 23443314302042 in words is "twenty-three trillion, four hundred forty-three billion, three hundred fourteen million, three hundred two thousand, forty-two".
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