Base | Representation |
---|---|
bin | 1010101100100011101110… |
… | …01100010010111111111001 |
3 | 10002021121102200221001100120 |
4 | 11112101313030102333321 |
5 | 11040333000100001040 |
6 | 122005301521123453 |
7 | 4645232161341234 |
oct | 526216714227771 |
9 | 102247380831316 |
10 | 23521240625145 |
11 | 754933615426a |
12 | 277a6a7a89589 |
13 | 1018074685a43 |
14 | 5b461132641b |
15 | 2abc94d3b7d0 |
hex | 156477312ff9 |
23521240625145 has 32 divisors (see below), whose sum is σ = 38675263052160. Its totient is φ = 12197992550400.
The previous prime is 23521240625143. The next prime is 23521240625153. The reversal of 23521240625145 is 54152604212532.
It is not a de Polignac number, because 23521240625145 - 21 = 23521240625143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23521240625097 and 23521240625106.
It is not an unprimeable number, because it can be changed into a prime (23521240625143) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12347115 + ... + 14124224.
It is an arithmetic number, because the mean of its divisors is an integer number (1208601970380).
Almost surely, 223521240625145 is an apocalyptic number.
It is an amenable number.
23521240625145 is a deficient number, since it is larger than the sum of its proper divisors (15154022427015).
23521240625145 is a wasteful number, since it uses less digits than its factorization.
23521240625145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26472985.
The product of its (nonzero) digits is 576000, while the sum is 42.
Adding to 23521240625145 its reverse (54152604212532), we get a palindrome (77673844837677).
The spelling of 23521240625145 in words is "twenty-three trillion, five hundred twenty-one billion, two hundred forty million, six hundred twenty-five thousand, one hundred forty-five".
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