Base | Representation |
---|---|
bin | 110101100000101100100010… |
… | …001011100100111101000101 |
3 | 1010212021121012200002022000220 |
4 | 311200230202023210331011 |
5 | 221321331042422211423 |
6 | 2152311120013454553 |
7 | 100366664345265543 |
oct | 6540544213447505 |
9 | 1125247180068026 |
10 | 235343306444613 |
11 | 68a95599111a54 |
12 | 2248b1391a1459 |
13 | a141a176a1033 |
14 | 421896923cd93 |
15 | 1c31c45b579e3 |
hex | d60b222e4f45 |
235343306444613 has 4 divisors (see below), whose sum is σ = 313791075259488. Its totient is φ = 156895537629740.
The previous prime is 235343306444563. The next prime is 235343306444629. The reversal of 235343306444613 is 316444603343532.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 235343306444613 - 28 = 235343306444357 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (235343306444513) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39223884407433 + ... + 39223884407438.
It is an arithmetic number, because the mean of its divisors is an integer number (78447768814872).
Almost surely, 2235343306444613 is an apocalyptic number.
It is an amenable number.
235343306444613 is a deficient number, since it is larger than the sum of its proper divisors (78447768814875).
235343306444613 is an equidigital number, since it uses as much as digits as its factorization.
235343306444613 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78447768814874.
The product of its (nonzero) digits is 22394880, while the sum is 51.
The spelling of 235343306444613 in words is "two hundred thirty-five trillion, three hundred forty-three billion, three hundred six million, four hundred forty-four thousand, six hundred thirteen".
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