Base | Representation |
---|---|
bin | 1010101101011111101101… |
… | …00010110101011110001111 |
3 | 10002101200112212111221102222 |
4 | 11112233312202311132033 |
5 | 11041344422123323043 |
6 | 122032145112405555 |
7 | 4650452151530561 |
oct | 526576642653617 |
9 | 102350485457388 |
10 | 23553442011023 |
11 | 7560a5aa84071 |
12 | 27849940a68bb |
13 | 101b106b46222 |
14 | 5b5dc7c8d331 |
15 | 2aca2bd57d68 |
hex | 156bf68b578f |
23553442011023 has 4 divisors (see below), whose sum is σ = 23567224015080. Its totient is φ = 23539660006968.
The previous prime is 23553442010999. The next prime is 23553442011067. The reversal of 23553442011023 is 32011024435532.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23553442011023 - 28 = 23553442010767 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23553442016023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6890999465 + ... + 6891002882.
It is an arithmetic number, because the mean of its divisors is an integer number (5891806003770).
Almost surely, 223553442011023 is an apocalyptic number.
23553442011023 is a deficient number, since it is larger than the sum of its proper divisors (13782004057).
23553442011023 is a wasteful number, since it uses less digits than its factorization.
23553442011023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13782004056.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 23553442011023 its reverse (32011024435532), we get a palindrome (55564466446555).
The spelling of 23553442011023 in words is "twenty-three trillion, five hundred fifty-three billion, four hundred forty-two million, eleven thousand, twenty-three".
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