Base | Representation |
---|---|
bin | 110110101010111000001000… |
… | …011001101111011100001011 |
3 | 1011112022221020201002212020201 |
4 | 312222320020121233130023 |
5 | 223003341132013132230 |
6 | 2211213023125033031 |
7 | 101434201061546065 |
oct | 6652701031573413 |
9 | 1145287221085221 |
10 | 240441000130315 |
11 | 6a680501320536 |
12 | 22b730b0555777 |
13 | a4216484cb7ca |
14 | 4353599612735 |
15 | 1cbe64ed965ca |
hex | daae0866f70b |
240441000130315 has 64 divisors (see below), whose sum is σ = 302166292561920. Its totient is φ = 183323812953600.
The previous prime is 240441000130313. The next prime is 240441000130343. The reversal of 240441000130315 is 513031000144042.
It is not a de Polignac number, because 240441000130315 - 21 = 240441000130313 is a prime.
It is a super-2 number, since 2×2404410001303152 (a number of 30 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (240441000130313) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 102011454117 + ... + 102011456473.
It is an arithmetic number, because the mean of its divisors is an integer number (4721348321280).
Almost surely, 2240441000130315 is an apocalyptic number.
240441000130315 is a deficient number, since it is larger than the sum of its proper divisors (61725292431605).
240441000130315 is a wasteful number, since it uses less digits than its factorization.
240441000130315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5332.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 240441000130315 its reverse (513031000144042), we get a palindrome (753472000274357).
The spelling of 240441000130315 in words is "two hundred forty trillion, four hundred forty-one billion, one hundred thirty thousand, three hundred fifteen".
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