Base | Representation |
---|---|
bin | 110110110100100000111101… |
… | …001110101111000010101101 |
3 | 1011121200020210022121110000001 |
4 | 312310200331032233002231 |
5 | 223100214040204314013 |
6 | 2212441155430104301 |
7 | 101533065550504516 |
oct | 6664407516570255 |
9 | 1147606708543001 |
10 | 241103311401133 |
11 | 6a906381810065 |
12 | 2305b52b1ab091 |
13 | a46bc386a645c |
14 | 43776692ada0d |
15 | 1cd19b5312ddd |
hex | db483d3af0ad |
241103311401133 has 16 divisors (see below), whose sum is σ = 242541386176320. Its totient is φ = 239668938835200.
The previous prime is 241103311401089. The next prime is 241103311401167. The reversal of 241103311401133 is 331104113301142.
It is a cyclic number.
It is not a de Polignac number, because 241103311401133 - 213 = 241103311392941 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (241103311408133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1444436083 + ... + 1444602991.
It is an arithmetic number, because the mean of its divisors is an integer number (15158836636020).
Almost surely, 2241103311401133 is an apocalyptic number.
It is an amenable number.
241103311401133 is a deficient number, since it is larger than the sum of its proper divisors (1438074775187).
241103311401133 is a wasteful number, since it uses less digits than its factorization.
241103311401133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 177948.
The product of its (nonzero) digits is 2592, while the sum is 28.
Adding to 241103311401133 its reverse (331104113301142), we get a palindrome (572207424702275).
The spelling of 241103311401133 in words is "two hundred forty-one trillion, one hundred three billion, three hundred eleven million, four hundred one thousand, one hundred thirty-three".
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