Base | Representation |
---|---|
bin | 110110110110001111110111… |
… | …011110100000000000111111 |
3 | 1011122002122011211012220102220 |
4 | 312312033313132200000333 |
5 | 223104141433423304210 |
6 | 2213012012452420423 |
7 | 101544512643633102 |
oct | 6666176736400077 |
9 | 1148078154186386 |
10 | 241222400213055 |
11 | 6a9519332a1088 |
12 | 2307a625917713 |
13 | a47a236b7a881 |
14 | 437d3255c6739 |
15 | 1cd4b352cbc70 |
hex | db63f77a003f |
241222400213055 has 8 divisors (see below), whose sum is σ = 385955840340912. Its totient is φ = 128651946780288.
The previous prime is 241222400213033. The next prime is 241222400213111. The reversal of 241222400213055 is 550312004222142.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 241222400213055 - 25 = 241222400213023 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8040746673754 + ... + 8040746673783.
It is an arithmetic number, because the mean of its divisors is an integer number (48244480042614).
Almost surely, 2241222400213055 is an apocalyptic number.
241222400213055 is a deficient number, since it is larger than the sum of its proper divisors (144733440127857).
241222400213055 is a wasteful number, since it uses less digits than its factorization.
241222400213055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16081493347545.
The product of its (nonzero) digits is 38400, while the sum is 33.
Adding to 241222400213055 its reverse (550312004222142), we get a palindrome (791534404435197).
The spelling of 241222400213055 in words is "two hundred forty-one trillion, two hundred twenty-two billion, four hundred million, two hundred thirteen thousand, fifty-five".
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