Base | Representation |
---|---|
bin | 11100110000100… |
… | …00100101110001 |
3 | 121210221021122212 |
4 | 32120100211301 |
5 | 443224143213 |
6 | 35534341505 |
7 | 5656336610 |
oct | 1630204561 |
9 | 553837585 |
10 | 241240433 |
11 | 1141a0565 |
12 | 6895a895 |
13 | 3ac96625 |
14 | 24079877 |
15 | 162a39a8 |
hex | e610971 |
241240433 has 16 divisors (see below), whose sum is σ = 283118976. Its totient is φ = 201240960.
The previous prime is 241240427. The next prime is 241240451. The reversal of 241240433 is 334042142.
It is a cyclic number.
It is not a de Polignac number, because 241240433 - 218 = 240978289 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 241240399 and 241240408.
It is not an unprimeable number, because it can be changed into a prime (241240403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 160835 + ... + 162327.
It is an arithmetic number, because the mean of its divisors is an integer number (17694936).
Almost surely, 2241240433 is an apocalyptic number.
It is an amenable number.
241240433 is a deficient number, since it is larger than the sum of its proper divisors (41878543).
241240433 is a wasteful number, since it uses less digits than its factorization.
241240433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2104.
The product of its (nonzero) digits is 2304, while the sum is 23.
The square root of 241240433 is about 15531.9165913290. The cubic root of 241240433 is about 622.5153046457.
Adding to 241240433 its reverse (334042142), we get a palindrome (575282575).
The spelling of 241240433 in words is "two hundred forty-one million, two hundred forty thousand, four hundred thirty-three".
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