Base | Representation |
---|---|
bin | 110110110110101100100100… |
… | …101000010100001111010111 |
3 | 1011122012120201212211221102021 |
4 | 312312230210220110033113 |
5 | 223110143044432011210 |
6 | 2213034111141554011 |
7 | 101546653520213326 |
oct | 6666544450241727 |
9 | 1148176655757367 |
10 | 241253222532055 |
11 | 6a963a0a72a598 |
12 | 230845a8115907 |
13 | a48010970b656 |
14 | 4380a0ad2a0bd |
15 | 1cd583b1dabda |
hex | db6b24a143d7 |
241253222532055 has 16 divisors (see below), whose sum is σ = 296237861742240. Its totient is φ = 188513289030528.
The previous prime is 241253222531953. The next prime is 241253222532059. The reversal of 241253222532055 is 550235222352142.
It is a cyclic number.
It is not a de Polignac number, because 241253222532055 - 227 = 241253088314327 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (241253222532059) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 47098389 + ... + 51968881.
It is an arithmetic number, because the mean of its divisors is an integer number (18514866358890).
Almost surely, 2241253222532055 is an apocalyptic number.
241253222532055 is a deficient number, since it is larger than the sum of its proper divisors (54984639210185).
241253222532055 is a wasteful number, since it uses less digits than its factorization.
241253222532055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5100930.
The product of its (nonzero) digits is 1440000, while the sum is 43.
Adding to 241253222532055 its reverse (550235222352142), we get a palindrome (791488444884197).
The spelling of 241253222532055 in words is "two hundred forty-one trillion, two hundred fifty-three billion, two hundred twenty-two million, five hundred thirty-two thousand, fifty-five".
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