Base | Representation |
---|---|
bin | 110110110110101101100100… |
… | …111010111001100010011101 |
3 | 1011122012200112001110011112221 |
4 | 312312231210322321202131 |
5 | 223110202302043121440 |
6 | 2213034410152225341 |
7 | 101550022325243233 |
oct | 6666554472714235 |
9 | 1148180461404487 |
10 | 241254301145245 |
11 | 6a964413567653 |
12 | 2308484939b251 |
13 | a48024c0118cb |
14 | 4380ab029c953 |
15 | 1cd58a0c49d4a |
hex | db6b64eb989d |
241254301145245 has 16 divisors (see below), whose sum is σ = 296587634353920. Its totient is φ = 188282470723200.
The previous prime is 241254301145219. The next prime is 241254301145257. The reversal of 241254301145245 is 542541103452142.
It is not a de Polignac number, because 241254301145245 - 233 = 241245711210653 is a prime.
It is a super-2 number, since 2×2412543011452452 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39551601 + ... + 45241990.
It is an arithmetic number, because the mean of its divisors is an integer number (18536727147120).
Almost surely, 2241254301145245 is an apocalyptic number.
It is an amenable number.
241254301145245 is a deficient number, since it is larger than the sum of its proper divisors (55333333208675).
241254301145245 is a wasteful number, since it uses less digits than its factorization.
241254301145245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84807516.
The product of its (nonzero) digits is 768000, while the sum is 43.
Adding to 241254301145245 its reverse (542541103452142), we get a palindrome (783795404597387).
The spelling of 241254301145245 in words is "two hundred forty-one trillion, two hundred fifty-four billion, three hundred one million, one hundred forty-five thousand, two hundred forty-five".
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