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2413140440042 = 21206570220021
BaseRepresentation
bin100011000111011010011…
…000001111001111101010
322112200201220110201221102
4203013122120033033222
5304014102423040132
65044325330241402
7336225604205633
oct43073230171752
98480656421842
102413140440042
11850452960292
1232b823a26262
131467343a6b07
1484b21cd888a
1542b88319c62
hex231da60f3ea

2413140440042 has 4 divisors (see below), whose sum is σ = 3619710660066. Its totient is φ = 1206570220020.

The previous prime is 2413140440003. The next prime is 2413140440057. The reversal of 2413140440042 is 2400440413142.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1787726769481 + 625413670561 = 1337059^2 + 790831^2 .

It is a junction number, because it is equal to n+sod(n) for n = 2413140439987 and 2413140440014.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 603285110009 + ... + 603285110012.

Almost surely, 22413140440042 is an apocalyptic number.

2413140440042 is a deficient number, since it is larger than the sum of its proper divisors (1206570220024).

2413140440042 is a wasteful number, since it uses less digits than its factorization.

2413140440042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1206570220023.

The product of its (nonzero) digits is 12288, while the sum is 29.

Adding to 2413140440042 its reverse (2400440413142), we get a palindrome (4813580853184).

The spelling of 2413140440042 in words is "two trillion, four hundred thirteen billion, one hundred forty million, four hundred forty thousand, forty-two".

Divisors: 1 2 1206570220021 2413140440042