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2413211213035 = 57394717468683
BaseRepresentation
bin100011000111011110100…
…110001101110011101011
322112200220211122101020101
4203013132212031303223
5304014224032304120
65044340335210231
7336230423602120
oct43073646156353
98480824571211
102413211213035
118504898aa067
1232b843676977
13146745c5641c
1484b2b47c747
1542b8e64990a
hex231de98dceb

2413211213035 has 16 divisors (see below), whose sum is σ = 3310385492736. Its totient is φ = 1654354060128.

The previous prime is 2413211213009. The next prime is 2413211213041. The reversal of 2413211213035 is 5303121123142.

It is not a de Polignac number, because 2413211213035 - 25 = 2413211213003 is a prime.

It is a super-2 number, since 2×24132112130352 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2413211212994 and 2413211213012.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8596197 + ... + 8872486.

It is an arithmetic number, because the mean of its divisors is an integer number (206899093296).

Almost surely, 22413211213035 is an apocalyptic number.

2413211213035 is a deficient number, since it is larger than the sum of its proper divisors (897174279701).

2413211213035 is a wasteful number, since it uses less digits than its factorization.

2413211213035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17472642.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 2413211213035 its reverse (5303121123142), we get a palindrome (7716332336177).

The spelling of 2413211213035 in words is "two trillion, four hundred thirteen billion, two hundred eleven million, two hundred thirteen thousand, thirty-five".

Divisors: 1 5 7 35 3947 19735 27629 138145 17468683 87343415 122280781 611403905 68948891801 344744459005 482642242607 2413211213035