Base | Representation |
---|---|
bin | 100011000111011110100… |
… | …110001101110011101011 |
3 | 22112200220211122101020101 |
4 | 203013132212031303223 |
5 | 304014224032304120 |
6 | 5044340335210231 |
7 | 336230423602120 |
oct | 43073646156353 |
9 | 8480824571211 |
10 | 2413211213035 |
11 | 8504898aa067 |
12 | 32b843676977 |
13 | 146745c5641c |
14 | 84b2b47c747 |
15 | 42b8e64990a |
hex | 231de98dceb |
2413211213035 has 16 divisors (see below), whose sum is σ = 3310385492736. Its totient is φ = 1654354060128.
The previous prime is 2413211213009. The next prime is 2413211213041. The reversal of 2413211213035 is 5303121123142.
It is not a de Polignac number, because 2413211213035 - 25 = 2413211213003 is a prime.
It is a super-2 number, since 2×24132112130352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2413211212994 and 2413211213012.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8596197 + ... + 8872486.
It is an arithmetic number, because the mean of its divisors is an integer number (206899093296).
Almost surely, 22413211213035 is an apocalyptic number.
2413211213035 is a deficient number, since it is larger than the sum of its proper divisors (897174279701).
2413211213035 is a wasteful number, since it uses less digits than its factorization.
2413211213035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17472642.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 2413211213035 its reverse (5303121123142), we get a palindrome (7716332336177).
The spelling of 2413211213035 in words is "two trillion, four hundred thirteen billion, two hundred eleven million, two hundred thirteen thousand, thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •