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2413211213041 is a prime number
BaseRepresentation
bin100011000111011110100…
…110001101110011110001
322112200220211122101020121
4203013132212031303301
5304014224032304131
65044340335210241
7336230423602126
oct43073646156361
98480824571217
102413211213041
118504898aa072
1232b843676981
13146745c56425
1484b2b47c74d
1542b8e649911
hex231de98dcf1

2413211213041 has 2 divisors, whose sum is σ = 2413211213042. Its totient is φ = 2413211213040.

The previous prime is 2413211213009. The next prime is 2413211213057. The reversal of 2413211213041 is 1403121123142.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2292208112016 + 121003101025 = 1514004^2 + 347855^2 .

It is a cyclic number.

It is not a de Polignac number, because 2413211213041 - 25 = 2413211213009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2413211212997 and 2413211213015.

It is not a weakly prime, because it can be changed into another prime (2413211213081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1206605606520 + 1206605606521.

It is an arithmetic number, because the mean of its divisors is an integer number (1206605606521).

Almost surely, 22413211213041 is an apocalyptic number.

It is an amenable number.

2413211213041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2413211213041 is an equidigital number, since it uses as much as digits as its factorization.

2413211213041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 2413211213041 its reverse (1403121123142), we get a palindrome (3816332336183).

The spelling of 2413211213041 in words is "two trillion, four hundred thirteen billion, two hundred eleven million, two hundred thirteen thousand, forty-one".