Base | Representation |
---|---|
bin | 1110000011000000001… |
… | …1100100111000010001 |
3 | 212001220022110100022020 |
4 | 3200300003210320101 |
5 | 12423213022144213 |
6 | 302510215402053 |
7 | 23302146442356 |
oct | 3406003447021 |
9 | 761808410266 |
10 | 241324412433 |
11 | 93388380975 |
12 | 3a92b083329 |
13 | 199ab8a6320 |
14 | b97452662d |
15 | 642636e923 |
hex | 38300e4e11 |
241324412433 has 16 divisors (see below), whose sum is σ = 347610236736. Its totient is φ = 148038845760.
The previous prime is 241324412431. The next prime is 241324412479. The reversal of 241324412433 is 334214423142.
It is not a de Polignac number, because 241324412433 - 21 = 241324412431 is a prime.
It is a super-2 number, since 2×2413244124332 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 241324412394 and 241324412403.
It is not an unprimeable number, because it can be changed into a prime (241324412431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9747583 + ... + 9772308.
It is an arithmetic number, because the mean of its divisors is an integer number (21725639796).
Almost surely, 2241324412433 is an apocalyptic number.
It is an amenable number.
241324412433 is a deficient number, since it is larger than the sum of its proper divisors (106285824303).
241324412433 is a wasteful number, since it uses less digits than its factorization.
241324412433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19520224.
The product of its digits is 55296, while the sum is 33.
Adding to 241324412433 its reverse (334214423142), we get a palindrome (575538835575).
The spelling of 241324412433 in words is "two hundred forty-one billion, three hundred twenty-four million, four hundred twelve thousand, four hundred thirty-three".
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