Base | Representation |
---|---|
bin | 1010111110010110010110… |
… | …00001010111111101010111 |
3 | 10011110001021200020220111111 |
4 | 11133023023001113331113 |
5 | 11130341411243412210 |
6 | 123154155441315451 |
7 | 5040342435621415 |
oct | 537131301277527 |
9 | 104401250226444 |
10 | 24132532404055 |
11 | 7764605454449 |
12 | 2859068335b87 |
13 | 10608c381a71a |
14 | 5d60411102b5 |
15 | 2bcb2118188a |
hex | 15f2cb057f57 |
24132532404055 has 16 divisors (see below), whose sum is σ = 30767292018720. Its totient is φ = 18136508971392.
The previous prime is 24132532404047. The next prime is 24132532404073. The reversal of 24132532404055 is 55040423523142.
It is a cyclic number.
It is not a de Polignac number, because 24132532404055 - 23 = 24132532404047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 24132532403999 and 24132532404017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2249065689 + ... + 2249076418.
It is an arithmetic number, because the mean of its divisors is an integer number (1922955751170).
Almost surely, 224132532404055 is an apocalyptic number.
24132532404055 is a deficient number, since it is larger than the sum of its proper divisors (6634759614665).
24132532404055 is a wasteful number, since it uses less digits than its factorization.
24132532404055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4498142178.
The product of its (nonzero) digits is 576000, while the sum is 40.
Adding to 24132532404055 its reverse (55040423523142), we get a palindrome (79172955927197).
The spelling of 24132532404055 in words is "twenty-four trillion, one hundred thirty-two billion, five hundred thirty-two million, four hundred four thousand, fifty-five".
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