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24134012430113 = 43954974971367
BaseRepresentation
bin1010111110011001000110…
…01111001110011100100001
310011110012002211012000120102
411133030203033032130201
511130402424140230423
6123155002351352145
75040424216626245
oct537144317163441
9104405084160512
1024134012430113
1177651a4931983
1228593bbb22655
131060a9b3383a1
145d61418d4425
152bcbab082c28
hex15f3233ce721

24134012430113 has 4 divisors (see below), whose sum is σ = 24188987401920. Its totient is φ = 24079037458308.

The previous prime is 24134012430053. The next prime is 24134012430137. The reversal of 24134012430113 is 31103421043142.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 24134012430113 - 226 = 24133945321249 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (24134012430193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27487485245 + ... + 27487486122.

It is an arithmetic number, because the mean of its divisors is an integer number (6047246850480).

Almost surely, 224134012430113 is an apocalyptic number.

It is an amenable number.

24134012430113 is a deficient number, since it is larger than the sum of its proper divisors (54974971807).

24134012430113 is an equidigital number, since it uses as much as digits as its factorization.

24134012430113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54974971806.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 24134012430113 its reverse (31103421043142), we get a palindrome (55237433473255).

The spelling of 24134012430113 in words is "twenty-four trillion, one hundred thirty-four billion, twelve million, four hundred thirty thousand, one hundred thirteen".

Divisors: 1 439 54974971367 24134012430113