Base | Representation |
---|---|
bin | 1010111110011001000110… |
… | …01111001110011011100101 |
3 | 10011110012002211012000111012 |
4 | 11133030203033032123211 |
5 | 11130402424140230203 |
6 | 123155002351352005 |
7 | 5040424216626131 |
oct | 537144317163345 |
9 | 104405084160435 |
10 | 24134012430053 |
11 | 77651a4931929 |
12 | 28593bbb22605 |
13 | 1060a9b338356 |
14 | 5d61418d43c1 |
15 | 2bcbab082bd8 |
hex | 15f3233ce6e5 |
24134012430053 has 2 divisors, whose sum is σ = 24134012430054. Its totient is φ = 24134012430052.
The previous prime is 24134012430041. The next prime is 24134012430137. The reversal of 24134012430053 is 35003421043142.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18032312123809 + 6101700306244 = 4246447^2 + 2470162^2 .
It is a cyclic number.
It is not a de Polignac number, because 24134012430053 - 28 = 24134012429797 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (24134012430953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12067006215026 + 12067006215027.
It is an arithmetic number, because the mean of its divisors is an integer number (12067006215027).
Almost surely, 224134012430053 is an apocalyptic number.
It is an amenable number.
24134012430053 is a deficient number, since it is larger than the sum of its proper divisors (1).
24134012430053 is an equidigital number, since it uses as much as digits as its factorization.
24134012430053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 32.
Adding to 24134012430053 its reverse (35003421043142), we get a palindrome (59137433473195).
The spelling of 24134012430053 in words is "twenty-four trillion, one hundred thirty-four billion, twelve million, four hundred thirty thousand, fifty-three".
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