2413433441141 has 4 divisors (see below), whose sum is σ = 2413440960000. Its totient is φ = 2413425922284.

The previous prime is 2413433441131. The next prime is 2413433441161. The reversal of 2413433441141 is 1411443343142.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2413433441141 - 2²⁶ = 2413366332277 is a prime.

It is a super-2 number, since 2×2413433441141² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2413433441131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3255431 + ... + 3927428.

It is an arithmetic number, because the mean of its divisors is an integer number (603360240000).

Almost surely, 2^{2413433441141} is an apocalyptic number.

It is an amenable number.

2413433441141 is a deficient number, since it is larger than the sum of its proper divisors (7518859).

2413433441141 is an equidigital number, since it uses as much as digits as its factorization.

2413433441141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7518858.

The product of its digits is 55296, while the sum is 35.

Adding to 2413433441141 its reverse (1411443343142), we get a palindrome (3824876784283).

The spelling of 2413433441141 in words is "two trillion, four hundred thirteen billion, four hundred thirty-three million, four hundred forty-one thousand, one hundred forty-one".