Base | Representation |
---|---|
bin | 1110000011000100111… |
… | …1110111010111111101 |
3 | 212001221201002101100211 |
4 | 3200301033313113331 |
5 | 12423233132124013 |
6 | 302512212152421 |
7 | 23302511434540 |
oct | 3406117672775 |
9 | 761851071324 |
10 | 241344411133 |
11 | 933986a0221 |
12 | 3a935908711 |
13 | 199b2a88c87 |
14 | b977050857 |
15 | 6427ec023d |
hex | 38313f75fd |
241344411133 has 4 divisors (see below), whose sum is σ = 275822184160. Its totient is φ = 206866638108.
The previous prime is 241344411109. The next prime is 241344411223. The reversal of 241344411133 is 331114443142.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 241344411133 - 217 = 241344280061 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 241344411095 and 241344411104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (241344417133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17238886503 + ... + 17238886516.
It is an arithmetic number, because the mean of its divisors is an integer number (68955546040).
Almost surely, 2241344411133 is an apocalyptic number.
It is an amenable number.
241344411133 is a deficient number, since it is larger than the sum of its proper divisors (34477773027).
241344411133 is an equidigital number, since it uses as much as digits as its factorization.
241344411133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34477773026.
The product of its digits is 13824, while the sum is 31.
Adding to 241344411133 its reverse (331114443142), we get a palindrome (572458854275).
The spelling of 241344411133 in words is "two hundred forty-one billion, three hundred forty-four million, four hundred eleven thousand, one hundred thirty-three".
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