241401323141345 has 4 divisors (see below), whose sum is σ = 289681587769620. Its totient is φ = 193121058513072.

The previous prime is 241401323141333. The next prime is 241401323141357. The reversal of 241401323141345 is 543141323104142.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (241401323141333) and next prime (241401323141357).

It can be written as a sum of positive squares in 2 ways, for example, as 155142868164496 + 86258454976849 = 12455636^2 + 9287543^2 .

It is a cyclic number.

It is not a de Polignac number, because 241401323141345 - 2²⁰ = 241401322092769 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 241401323141299 and 241401323141308.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24140132314130 + ... + 24140132314139.

It is an arithmetic number, because the mean of its divisors is an integer number (72420396942405).

Almost surely, 2^{241401323141345} is an apocalyptic number.

It is an amenable number.

241401323141345 is a deficient number, since it is larger than the sum of its proper divisors (48280264628275).

241401323141345 is an equidigital number, since it uses as much as digits as its factorization.

241401323141345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48280264628274.

The product of its (nonzero) digits is 138240, while the sum is 38.

Adding to 241401323141345 its reverse (543141323104142), we get a palindrome (784542646245487).

The spelling of 241401323141345 in words is "two hundred forty-one trillion, four hundred one billion, three hundred twenty-three million, one hundred forty-one thousand, three hundred forty-five".