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241433000433 = 3329308343551
BaseRepresentation
bin1110000011011010000…
…1110011100111110001
3212002011212210012001000
43200312201303213301
512423423322003213
6302525055032213
723304635433432
oct3406641634761
9762155705030
10241433000433
11934336a8719
123a95b50b669
13199c8235a91
14b984b11489
156430b6dc73
hex38368739f1

241433000433 has 16 divisors (see below), whose sum is σ = 370012262400. Its totient is φ = 155405149200.

The previous prime is 241433000401. The next prime is 241433000441. The reversal of 241433000433 is 334000334142.

It is not a de Polignac number, because 241433000433 - 25 = 241433000401 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 241433000397 and 241433000406.

It is not an unprimeable number, because it can be changed into a prime (241433000483) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 154170993 + ... + 154172558.

It is an arithmetic number, because the mean of its divisors is an integer number (23125766400).

Almost surely, 2241433000433 is an apocalyptic number.

It is an amenable number.

241433000433 is a deficient number, since it is larger than the sum of its proper divisors (128579261967).

241433000433 is a wasteful number, since it uses less digits than its factorization.

241433000433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 308343589 (or 308343583 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 27.

Adding to 241433000433 its reverse (334000334142), we get a palindrome (575433334575).

The spelling of 241433000433 in words is "two hundred forty-one billion, four hundred thirty-three million, four hundred thirty-three", and thus it is an aban number.

Divisors: 1 3 9 27 29 87 261 783 308343551 925030653 2775091959 8325275877 8941962979 26825888937 80477666811 241433000433