Base | Representation |
---|---|
bin | 110111000001110000100011… |
… | …010101011101101010101111 |
3 | 1011201220020220122201201122122 |
4 | 313001300203111131222233 |
5 | 223210121430431232421 |
6 | 2214415231542103155 |
7 | 101655614624245535 |
oct | 6701604325355257 |
9 | 1151806818651578 |
10 | 242013410024111 |
11 | 70127346755860 |
12 | 231879a141aabb |
13 | a5069c74007cb |
14 | 43a972396c155 |
15 | 1cea4ce1ce2ab |
hex | dc1c2355daaf |
242013410024111 has 8 divisors (see below), whose sum is σ = 264023523945984. Its totient is φ = 220004778573720.
The previous prime is 242013410024021. The next prime is 242013410024123. The reversal of 242013410024111 is 111420014310242.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 242013410024111 - 218 = 242013409761967 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (242013410024611) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 370276511 + ... + 370929536.
It is an arithmetic number, because the mean of its divisors is an integer number (33002940493248).
Almost surely, 2242013410024111 is an apocalyptic number.
242013410024111 is a deficient number, since it is larger than the sum of its proper divisors (22010113921873).
242013410024111 is a wasteful number, since it uses less digits than its factorization.
242013410024111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 741235741.
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 242013410024111 its reverse (111420014310242), we get a palindrome (353433424334353).
The spelling of 242013410024111 in words is "two hundred forty-two trillion, thirteen billion, four hundred ten million, twenty-four thousand, one hundred eleven".
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